Optimal. Leaf size=307 \[ -\frac {\left (a^2-b^2\right ) \sin ^4(c+d x) \cos (c+d x)}{a b^2 d (a+b \sin (c+d x))}+\frac {3 a \left (4 a^2-3 b^2\right ) \sin (c+d x) \cos (c+d x)}{4 b^5 d}-\frac {\left (10 a^2-7 b^2\right ) \sin ^2(c+d x) \cos (c+d x)}{5 b^4 d}+\frac {\left (3 a^2-2 b^2\right ) \sin ^3(c+d x) \cos (c+d x)}{2 a b^3 d}+\frac {6 a^2 \left (2 a^4-3 a^2 b^2+b^4\right ) \tan ^{-1}\left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{b^7 d \sqrt {a^2-b^2}}-\frac {3 a x \left (8 a^4-8 a^2 b^2+b^4\right )}{4 b^7}-\frac {\left (30 a^4-25 a^2 b^2+b^4\right ) \cos (c+d x)}{5 b^6 d}-\frac {\sin ^4(c+d x) \cos (c+d x)}{5 b^2 d} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 1.02, antiderivative size = 307, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 7, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.241, Rules used = {2892, 3049, 3023, 2735, 2660, 618, 204} \[ -\frac {\left (-25 a^2 b^2+30 a^4+b^4\right ) \cos (c+d x)}{5 b^6 d}+\frac {6 a^2 \left (-3 a^2 b^2+2 a^4+b^4\right ) \tan ^{-1}\left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{b^7 d \sqrt {a^2-b^2}}-\frac {\left (a^2-b^2\right ) \sin ^4(c+d x) \cos (c+d x)}{a b^2 d (a+b \sin (c+d x))}+\frac {\left (3 a^2-2 b^2\right ) \sin ^3(c+d x) \cos (c+d x)}{2 a b^3 d}-\frac {\left (10 a^2-7 b^2\right ) \sin ^2(c+d x) \cos (c+d x)}{5 b^4 d}+\frac {3 a \left (4 a^2-3 b^2\right ) \sin (c+d x) \cos (c+d x)}{4 b^5 d}-\frac {3 a x \left (-8 a^2 b^2+8 a^4+b^4\right )}{4 b^7}-\frac {\sin ^4(c+d x) \cos (c+d x)}{5 b^2 d} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 204
Rule 618
Rule 2660
Rule 2735
Rule 2892
Rule 3023
Rule 3049
Rubi steps
\begin {align*} \int \frac {\cos ^4(c+d x) \sin ^3(c+d x)}{(a+b \sin (c+d x))^2} \, dx &=-\frac {\cos (c+d x) \sin ^4(c+d x)}{5 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{a b^2 d (a+b \sin (c+d x))}+\frac {\int \frac {\sin ^3(c+d x) \left (3 \left (8 a^2-5 b^2\right )-a b \sin (c+d x)-10 \left (3 a^2-2 b^2\right ) \sin ^2(c+d x)\right )}{a+b \sin (c+d x)} \, dx}{5 a b^2}\\ &=\frac {\left (3 a^2-2 b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{2 a b^3 d}-\frac {\cos (c+d x) \sin ^4(c+d x)}{5 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{a b^2 d (a+b \sin (c+d x))}+\frac {\int \frac {\sin ^2(c+d x) \left (-30 a \left (3 a^2-2 b^2\right )+6 a^2 b \sin (c+d x)+12 a \left (10 a^2-7 b^2\right ) \sin ^2(c+d x)\right )}{a+b \sin (c+d x)} \, dx}{20 a b^3}\\ &=-\frac {\left (10 a^2-7 b^2\right ) \cos (c+d x) \sin ^2(c+d x)}{5 b^4 d}+\frac {\left (3 a^2-2 b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{2 a b^3 d}-\frac {\cos (c+d x) \sin ^4(c+d x)}{5 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{a b^2 d (a+b \sin (c+d x))}+\frac {\int \frac {\sin (c+d x) \left (24 a^2 \left (10 a^2-7 b^2\right )-6 a b \left (5 a^2-2 b^2\right ) \sin (c+d x)-90 a^2 \left (4 a^2-3 b^2\right ) \sin ^2(c+d x)\right )}{a+b \sin (c+d x)} \, dx}{60 a b^4}\\ &=\frac {3 a \left (4 a^2-3 b^2\right ) \cos (c+d x) \sin (c+d x)}{4 b^5 d}-\frac {\left (10 a^2-7 b^2\right ) \cos (c+d x) \sin ^2(c+d x)}{5 b^4 d}+\frac {\left (3 a^2-2 b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{2 a b^3 d}-\frac {\cos (c+d x) \sin ^4(c+d x)}{5 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{a b^2 d (a+b \sin (c+d x))}+\frac {\int \frac {-90 a^3 \left (4 a^2-3 b^2\right )+6 a^2 b \left (20 a^2-11 b^2\right ) \sin (c+d x)+24 a \left (30 a^4-25 a^2 b^2+b^4\right ) \sin ^2(c+d x)}{a+b \sin (c+d x)} \, dx}{120 a b^5}\\ &=-\frac {\left (30 a^4-25 a^2 b^2+b^4\right ) \cos (c+d x)}{5 b^6 d}+\frac {3 a \left (4 a^2-3 b^2\right ) \cos (c+d x) \sin (c+d x)}{4 b^5 d}-\frac {\left (10 a^2-7 b^2\right ) \cos (c+d x) \sin ^2(c+d x)}{5 b^4 d}+\frac {\left (3 a^2-2 b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{2 a b^3 d}-\frac {\cos (c+d x) \sin ^4(c+d x)}{5 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{a b^2 d (a+b \sin (c+d x))}+\frac {\int \frac {-90 a^3 b \left (4 a^2-3 b^2\right )-90 a^2 \left (8 a^4-8 a^2 b^2+b^4\right ) \sin (c+d x)}{a+b \sin (c+d x)} \, dx}{120 a b^6}\\ &=-\frac {3 a \left (8 a^4-8 a^2 b^2+b^4\right ) x}{4 b^7}-\frac {\left (30 a^4-25 a^2 b^2+b^4\right ) \cos (c+d x)}{5 b^6 d}+\frac {3 a \left (4 a^2-3 b^2\right ) \cos (c+d x) \sin (c+d x)}{4 b^5 d}-\frac {\left (10 a^2-7 b^2\right ) \cos (c+d x) \sin ^2(c+d x)}{5 b^4 d}+\frac {\left (3 a^2-2 b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{2 a b^3 d}-\frac {\cos (c+d x) \sin ^4(c+d x)}{5 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{a b^2 d (a+b \sin (c+d x))}+\frac {\left (3 a^2 \left (2 a^4-3 a^2 b^2+b^4\right )\right ) \int \frac {1}{a+b \sin (c+d x)} \, dx}{b^7}\\ &=-\frac {3 a \left (8 a^4-8 a^2 b^2+b^4\right ) x}{4 b^7}-\frac {\left (30 a^4-25 a^2 b^2+b^4\right ) \cos (c+d x)}{5 b^6 d}+\frac {3 a \left (4 a^2-3 b^2\right ) \cos (c+d x) \sin (c+d x)}{4 b^5 d}-\frac {\left (10 a^2-7 b^2\right ) \cos (c+d x) \sin ^2(c+d x)}{5 b^4 d}+\frac {\left (3 a^2-2 b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{2 a b^3 d}-\frac {\cos (c+d x) \sin ^4(c+d x)}{5 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{a b^2 d (a+b \sin (c+d x))}+\frac {\left (6 a^2 \left (2 a^4-3 a^2 b^2+b^4\right )\right ) \operatorname {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{b^7 d}\\ &=-\frac {3 a \left (8 a^4-8 a^2 b^2+b^4\right ) x}{4 b^7}-\frac {\left (30 a^4-25 a^2 b^2+b^4\right ) \cos (c+d x)}{5 b^6 d}+\frac {3 a \left (4 a^2-3 b^2\right ) \cos (c+d x) \sin (c+d x)}{4 b^5 d}-\frac {\left (10 a^2-7 b^2\right ) \cos (c+d x) \sin ^2(c+d x)}{5 b^4 d}+\frac {\left (3 a^2-2 b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{2 a b^3 d}-\frac {\cos (c+d x) \sin ^4(c+d x)}{5 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{a b^2 d (a+b \sin (c+d x))}-\frac {\left (12 a^2 \left (2 a^4-3 a^2 b^2+b^4\right )\right ) \operatorname {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )}{b^7 d}\\ &=-\frac {3 a \left (8 a^4-8 a^2 b^2+b^4\right ) x}{4 b^7}+\frac {6 a^2 \left (2 a^4-3 a^2 b^2+b^4\right ) \tan ^{-1}\left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{b^7 \sqrt {a^2-b^2} d}-\frac {\left (30 a^4-25 a^2 b^2+b^4\right ) \cos (c+d x)}{5 b^6 d}+\frac {3 a \left (4 a^2-3 b^2\right ) \cos (c+d x) \sin (c+d x)}{4 b^5 d}-\frac {\left (10 a^2-7 b^2\right ) \cos (c+d x) \sin ^2(c+d x)}{5 b^4 d}+\frac {\left (3 a^2-2 b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{2 a b^3 d}-\frac {\cos (c+d x) \sin ^4(c+d x)}{5 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{a b^2 d (a+b \sin (c+d x))}\\ \end {align*}
________________________________________________________________________________________
Mathematica [A] time = 4.57, size = 378, normalized size = 1.23 \[ \frac {\frac {960 a^2 \left (2 a^4-3 a^2 b^2+b^4\right ) \tan ^{-1}\left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{\sqrt {a^2-b^2}}-\frac {960 a^6 c+960 a^6 d x+960 a^5 b c \sin (c+d x)+960 a^5 b d x \sin (c+d x)+240 a^4 b^2 \sin (2 (c+d x))-960 a^4 b^2 c-960 a^4 b^2 d x-960 a^3 b^3 c \sin (c+d x)-960 a^3 b^3 d x \sin (c+d x)+5 \left (8 a^3 b^3-5 a b^5\right ) \cos (3 (c+d x))-200 a^2 b^4 \sin (2 (c+d x))-10 a^2 b^4 \sin (4 (c+d x))+120 a^2 b^4 c+120 a^2 b^4 d x+60 a b \left (16 a^4-14 a^2 b^2+b^4\right ) \cos (c+d x)+120 a b^5 c \sin (c+d x)+120 a b^5 d x \sin (c+d x)-3 a b^5 \cos (5 (c+d x))+5 b^6 \sin (2 (c+d x))+4 b^6 \sin (4 (c+d x))+b^6 \sin (6 (c+d x))}{a+b \sin (c+d x)}}{160 b^7 d} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
fricas [A] time = 0.83, size = 649, normalized size = 2.11 \[ \left [\frac {6 \, a b^{5} \cos \left (d x + c\right )^{5} - 5 \, {\left (4 \, a^{3} b^{3} - a b^{5}\right )} \cos \left (d x + c\right )^{3} - 15 \, {\left (8 \, a^{6} - 8 \, a^{4} b^{2} + a^{2} b^{4}\right )} d x - 30 \, {\left (2 \, a^{5} - a^{3} b^{2} + {\left (2 \, a^{4} b - a^{2} b^{3}\right )} \sin \left (d x + c\right )\right )} \sqrt {-a^{2} + b^{2}} \log \left (\frac {{\left (2 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2} + 2 \, {\left (a \cos \left (d x + c\right ) \sin \left (d x + c\right ) + b \cos \left (d x + c\right )\right )} \sqrt {-a^{2} + b^{2}}}{b^{2} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2}}\right ) - 15 \, {\left (8 \, a^{5} b - 8 \, a^{3} b^{3} + a b^{5}\right )} \cos \left (d x + c\right ) - {\left (4 \, b^{6} \cos \left (d x + c\right )^{5} - 10 \, a^{2} b^{4} \cos \left (d x + c\right )^{3} + 15 \, {\left (8 \, a^{5} b - 8 \, a^{3} b^{3} + a b^{5}\right )} d x + 15 \, {\left (4 \, a^{4} b^{2} - 3 \, a^{2} b^{4}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{20 \, {\left (b^{8} d \sin \left (d x + c\right ) + a b^{7} d\right )}}, \frac {6 \, a b^{5} \cos \left (d x + c\right )^{5} - 5 \, {\left (4 \, a^{3} b^{3} - a b^{5}\right )} \cos \left (d x + c\right )^{3} - 15 \, {\left (8 \, a^{6} - 8 \, a^{4} b^{2} + a^{2} b^{4}\right )} d x - 60 \, {\left (2 \, a^{5} - a^{3} b^{2} + {\left (2 \, a^{4} b - a^{2} b^{3}\right )} \sin \left (d x + c\right )\right )} \sqrt {a^{2} - b^{2}} \arctan \left (-\frac {a \sin \left (d x + c\right ) + b}{\sqrt {a^{2} - b^{2}} \cos \left (d x + c\right )}\right ) - 15 \, {\left (8 \, a^{5} b - 8 \, a^{3} b^{3} + a b^{5}\right )} \cos \left (d x + c\right ) - {\left (4 \, b^{6} \cos \left (d x + c\right )^{5} - 10 \, a^{2} b^{4} \cos \left (d x + c\right )^{3} + 15 \, {\left (8 \, a^{5} b - 8 \, a^{3} b^{3} + a b^{5}\right )} d x + 15 \, {\left (4 \, a^{4} b^{2} - 3 \, a^{2} b^{4}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{20 \, {\left (b^{8} d \sin \left (d x + c\right ) + a b^{7} d\right )}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
giac [A] time = 0.23, size = 536, normalized size = 1.75 \[ -\frac {\frac {15 \, {\left (8 \, a^{5} - 8 \, a^{3} b^{2} + a b^{4}\right )} {\left (d x + c\right )}}{b^{7}} - \frac {120 \, {\left (2 \, a^{6} - 3 \, a^{4} b^{2} + a^{2} b^{4}\right )} {\left (\pi \left \lfloor \frac {d x + c}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\relax (a) + \arctan \left (\frac {a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + b}{\sqrt {a^{2} - b^{2}}}\right )\right )}}{\sqrt {a^{2} - b^{2}} b^{7}} + \frac {40 \, {\left (a^{4} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - a^{2} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + a^{5} - a^{3} b^{2}\right )}}{{\left (a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 2 \, b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + a\right )} b^{6}} + \frac {2 \, {\left (40 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 25 \, a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 100 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{8} - 120 \, a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{8} + 20 \, b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{8} + 80 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 10 \, a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 400 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} - 360 \, a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} + 600 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 440 \, a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 40 \, b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 80 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 10 \, a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 400 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 280 \, a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 40 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 25 \, a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 100 \, a^{4} - 80 \, a^{2} b^{2} + 4 \, b^{4}\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{5} b^{6}}}{20 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maple [B] time = 0.58, size = 1119, normalized size = 3.64 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
mupad [B] time = 12.32, size = 2390, normalized size = 7.79 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________